Question

plz someone help me out in this question

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Answer 1

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Tan theta + sec theta - 1/tan theta - sec theta+1 =sec theta +tan theta

$\huge\underline\mathbb\blue{Answer}$ $\huge\red{\ddot\smile}$

Here, i am holding the "THETA" as "A".

So, we can proceed our solution as under :  

L.H.S

(tan A + sec A - 1)/(tan A - sec A + 1)

= (tan A + sec A - sec²A + tan²A)/(tan A - sec A + 1)

= [tan A + sec A - {(sec A+tan A) (sec A - tan A)}]/[tan A - sec A + 1]

= [tan A + sec A (1 - sec A + tan A)]/(tan A - sec A + 1)

= tan A + sec A

= sin A/cos A + 1/cos A

= ( 1 + sin A ) / cos A

=R.H.S

ULTIMATELY,

L.H.S. = R.H.S. (PROVED)

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Answer 2

Thankyou so much for so maannyyyy thanksss....

thanks a million.....✨❤

Stay blessed always....❣

Stay Gold....❣

BORAHAE ❣