Question

PLZ SOMEONE HELP....
QUE-)Without finding the cubes, factorise: (x -2y)3 + (2y-3z)3 + (3z –x)3.

Answer 1

Answer:

0

Step-by-step explanation:

3x-6y+6y-9z+9z-3x

0

Answer 2

Answer:answer❣

❤❤hey dear here your answer

Step-by-step explanation:

Question:-Find the factories of (x-2y)^3+(3z-x)^3

✔Here your answer

we know that ,

a^3+b^3+c^3-3abc =(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

If

(a+b+c)=0

Then ,

a^3+b^3+c^3=3abc

And here,

If

a=(x-2y)

b=(2y-3z)

c=(3z-x)

Thus ,

(x-2y)+(2y-3z)+(3z-x)=0[a+b+c=0]

And last ,

(x-2y)^3+(2y-3z)^3+(3z-x)^3=3(x-2y)(2y-3z)(3z-x)

❤Hope it will help

❣please mark as brainlist