Math, asked by purbasha776, 7 months ago

plz someone help to do this no.plz​

Attachments:

Answers

Answered by renuagrawal393
1

Answer:

4x²+9y²+16z²=6xy+12yz+8xz

=>(2x)²+(3y)²+(4z)²-6xy-12yz-8xz=0

multiply by 2 on both sides

Since,

=> [(2x)²+(3y)²-12xy] + [(3y)²+(4z)²-24yz] + [(2x)²+(4z)²-16xz] =0

=> (2x-3y)² + (3y-4z)² +(2x-4z)² =0 .........(i)

For satisfying equation (i) Put

2x-3y=0

3y-4z=0

2x-4z=0

Hence,

2x=3y=4z proved

hope it helps you.....

Similar questions