Question

plz someone plz ans give ans in pic

Answer 1

Numerator :

$= > 9 - 2\sqrt{3}x - x^2$

$= > -(x^2 + 2\sqrt{3}x - 9)$

$= > -(x^2 + 3\sqrt{3}x - \sqrt{3}x - 3\sqrt{3} * \sqrt{3} )$

$= > -(x(x + 3\sqrt{3}) - \sqrt{3}(x + 3\sqrt{3}))$

$= > -(x - \sqrt{3})(x + 3\sqrt{3})$

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Now,

Denominator = 3 - x^2.

$= > (\sqrt{3} - x)(\sqrt{3} + x)$

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Now,

$= > \frac{9 - 2\sqrt{3}x^2 - x^2}{3 - x^2} = \frac{-(x - \sqrt{3})(x + 3\sqrt{3})}{(\sqrt{3} - x)(\sqrt{3} + x)}$

$= > \frac{(\sqrt{3} - x)(x + 3\sqrt{3})}{(\sqrt{3} - x)(\sqrt{3} + x)}$

$= > \frac{x + 3\sqrt{3}}{\sqrt{3} + x}$

Hope this helps!