Plz someone solve Q4......
I will mark brainliest
Answers
Answer:
When bulb B1 gets fused, the currents in B2 and .B3 remain same I2 = I3 = 1A, so their glow remains unaffected.
Answer:
Explanation:
the current in A1 and A3 will increase
and in A there will be the greatest flow of current
the current in A2 will be zero as the bulb is fused
the cuircuit will break
Current in ammeter A1 = 1 A
Current in ammeter A2 = 0
Current in ammeter A3 = 1 A
Current in ammeter A4 = 2A
Explanation:
(i) When bulb B1 will get fused, the currents in B2 and B3 are still same I2 = I3 = 1A.
Therefore, the glow of these bulbs will not be affected
(ii) When bulb B2 gets fused, the current in .B2 turns to be zero and currents in B1 and B3 remains 1 A.
therefore, Total current I = I1 + I2 + I3
= I + 0 + I = 2A
Current in ammeter A1 = 1 A
Current in ammeter A2 = 0
Current in ammeter A3 = 1 A
Current in ammeter A4 = 2A
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