Question

plz someone solve this its urgent
Questions 3 only a)

Answer 1

Plz. Mark it as brainliest answer.. ☺✌

Answer 2

x+2=0
$x = - 2 \\ satisfies \: \: \: the \: \: \: equation$
hence
${x}^{3} + ax + b = 0 \\ {( - 2)}^{3} - 2a + b = 0 \\ - 8 = 2a - b............. 1$



But x+3=0
x=-3

${x}^{3} + ax + b = 0 \\ {( - 3)}^{3} - 3a + b = 0 \\ - 27 = 3a - b............. 2$






Solving both equations simultaneously

$a = - 19 \\ b = - 30$