plz sove my question
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Step-by-step explanation:
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Step-by-step explanation:
In triangle ABC
∠B=90°,∠C=∅
BC²=AC²-AB²
=(a²+b²)²-(a²-b²)² {∵ Pythagoras theorem}
or BC= 2ab
∴ cos ∅= 2ab÷a²+ b²
tan ∅= a²-b²÷2ab
cosec∅=a²+b²÷2ab
sec ∅= a²+b²÷2ab
cot∅=2ab÷a²-b²
plz mark as brainliest......
nethrandevi:
Hope it helps
ok
thanks
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