Math, asked by karnanisha43, 10 months ago

Plz sove this question​

Attachments:

Answers

Answered by karannnn43
1

 {x}^{3}  +  {x}^{2}  + x +  {x}^{2} y + xy + y \\  \\ =  ({x}^{3}  +  {x}^{2}  + x) +(  {x}^{2} y + xy + y) \\  \\  = x( {x}^{2}  + x + 1) + y( {x}^{2}  + x + 1) \\  \\  = ( {x}^{2}   + x + 1)(x + y)

Hope you understand the concept used .

Answered by samya0001
1

Step-by-step explanation:

 {x}^{3}  +  {x}^{2}  + x +  {x}^{2} y + xy + y \\  xy <  {x}^{2}  + x + x  >  \\ xy( {x}^{2}  + 2x) \\  xy { (x +  \sqrt{2} )}^{2}  \\ xy( { x}^{2}  +  \sqrt{2} xy +  { \sqrt{2} }^{2} ) \\

I taken as I know from identity

Similar questions