plz take me answer fast
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Let says x is the unit digit and y is the tenth digit.
y+x = 9
y = 9-x
So, 10x + y = 10y + x + 27
10(9-x) + y = 10(9-x) + x + 27
18x = 108
x = 6 and y = 3
Hope u mark this answer as brainliest
y+x = 9
y = 9-x
So, 10x + y = 10y + x + 27
10(9-x) + y = 10(9-x) + x + 27
18x = 108
x = 6 and y = 3
Hope u mark this answer as brainliest
shivay8:
but ans is 36
hn bt bro maths h ye isliye ye answer v thk h bcoz frk ye h ki agr me x = 9-y leta to 63 and y = 9 - x liya h isliye ye answer h
but question is about all at original numberwhich is 36
Answered by
1
Let digit at ones place =x
and digit at unit pace=y
therefore,original number=x+10y
and, interchanging number=10x+y
According to question
x+y=9.......(1)
and,also given that(R=O-27....... for help)
10x+y=x+10y+27
10x-x+y-10y-27=0
9x-9y-27=0
take 9 common,
x-y-3=0
x-y=3......(2)
By solving (1) and (2)
x+y=9..(1)
x-y=3...(2)
from (1)
x=9-y...(3)
now put (3) in (2)
x-y=3
9-y-y=3
-2y=3-9
-2y=-6
y=6/2
y=3......(4)
now put (4) in (3
x=9-y
x=9-3
x=6
THEREFORE,
ORIGINAL NUMBER =X+10Y
6+10(3)
6+30
36, ANSWER
HOPE IT IS HELPFUL MATE;
PLS MARK IT AS BRAINLIEST!!!!
and digit at unit pace=y
therefore,original number=x+10y
and, interchanging number=10x+y
According to question
x+y=9.......(1)
and,also given that(R=O-27....... for help)
10x+y=x+10y+27
10x-x+y-10y-27=0
9x-9y-27=0
take 9 common,
x-y-3=0
x-y=3......(2)
By solving (1) and (2)
x+y=9..(1)
x-y=3...(2)
from (1)
x=9-y...(3)
now put (3) in (2)
x-y=3
9-y-y=3
-2y=3-9
-2y=-6
y=6/2
y=3......(4)
now put (4) in (3
x=9-y
x=9-3
x=6
THEREFORE,
ORIGINAL NUMBER =X+10Y
6+10(3)
6+30
36, ANSWER
HOPE IT IS HELPFUL MATE;
PLS MARK IT AS BRAINLIEST!!!!
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