Plz teach me :-
How to solve this type of questions briefly
You may be marked as brainliest if I am satisfied.
PRESS THE ABOVE PICTURE TO ACCESS THE QUESTION
This problem is a part of the chapter
Area of Trapezium and polygons.
Obtained from NCERT Textbook
Grade 8 question
Answers
Answer:
Step-by-step explanation: * the field is in the shape of a hexagon whose vertices are P, Q,R,S,T and L.
* PS is taken as diagonal.
* Vertices Q and R on one side of the diagonal PS and vertices T and L are on another side.
* the perpendicular drawn from A to PS is 50 m.
* in the field book the measurements are to be read upward from bottom.
* the field is divided into 4 triangles.
we can find the following measurements from the above diagram :-
AC=PC-PA ⇒110-40=70 m
CS=PS-PC⇒ 200-110=90 m
DS =PS-PD⇒200-160=40 m
BD= PD-PB⇒ 160-80=80 m
Area of ΔAPQ=1/2*b*h
=1/2*40*50
=1000 Sq m.
Area of trapezium ARQC =1/2h(a+b)
=1/2X70(50+60) ⇒ 1/2X70X110
=35X110 ⇒ 3850 Sq.m.
Area of ΔCRS=1/2 X CR X CS ⇒ 1/2 X 60 X 90
=2700 Sq.m.
Area of ΔSTD= 1/2 X TD X DS ⇒ 1/2 X 30 X 40
=600 Sq.m.
Area of rectangle BLTD = BL X BD
=30 X 80 ⇒ 2400 Sq.m.
Area of ΔPBL = 1/2 X PB X BL
=1/2 X 80 X 30 ⇒1200 Sq.m.
∴ Area of the field =1000+3850+2700+600+2400+1200
=11,750 Sq.m. Ans.
Hope it's helpful to you ^_^.