plz tell 3(x-4)+6=63
And if a= - 2
Then what will be 4(a-5)-2a+6?
Plz help
Answers
Answered by
0
Since x3+6∗x2>=0
Then, x2(x+6)>=0
i.e (x−0)2(x−(−6))>=0
This implies that\(x>=-6\)
Hence, x=-2 is a valid root, and s
Then, x2(x+6)>=0
i.e (x−0)2(x−(−6))>=0
This implies that\(x>=-6\)
Hence, x=-2 is a valid root, and s
Similar questions