Question

plz tell 5 question.. plz

Answer 1

Answer:

Step-by-step explanation:

Let t1 and t2 be the triangles formed by the diagonal -

Then area of quad = area of t1 + area of t2.

Area of t1 = 1/2 ☓ base ☓ height

Area of t1 = 1/2 ☓ 40 ☓ 16

Area of t1 = 320 cm2

Area of t2 = 1/2 ☓ 40 ☓ 12

Area of t2 = 240 cm2

Area of quad = 240 + 320

Area of quadrilateral = 560 cm2

➡️

Answer 2

given

diagonals ( d ) = 40 cm

height ( h1 ) = 16 cm

height ( h2 ) = 12 cm

Area of quadrilateral ==> 1/2 × d × ( h1 + h2 )

===> 1/2 × 40 × ( 16 + 12 )

===> 1/2 × 40 × ( 28 )

===> 20 × 28

===> 560 cm

Area of quadrilateral is 560 cm