Math, asked by Niyati2006, 11 months ago

plz tell

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Answered by classofankur
0

Answer:

a) (db)² = (ab)2 + (ad)²

(41)² = (40)2 + (ad)²

1681 - 1600 = (ad)²

81 = (ad)2 so ad = 9

b) area of trapezium = 1/2 * (sum of parallel sides) * h

= 1/2 * (40 + 15) * 9

= 1/2 * 55 * 9 = 247.5

c) area of triangle bcd = area of trapezium - area of triangle abd

= 247.5 - (1/2 * 40 * 9) = 247.5 - 180 = 67.5

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