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Given:- AD is median on BC i. e. BD = CD
To Prove:- BL = CM
Proof:- In ∆ BDL and ∆ CDM
angle BDL=angle CDM (vertically oppo. angle)
angle BLD = angle CMD (each 90°)
so, ∆ BDL ~ ∆ CDM
BL/BD = CM/CD
HENCE
BL = CM (bcoz BD = CD given)
hence proved.
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