Math, asked by shagunshukla07, 8 months ago

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Answered by harryoms
1

Answer:

Given:- AD is median on BC i. e. BD = CD

To Prove:- BL = CM

Proof:- In ∆ BDL and ∆ CDM

angle BDL=angle CDM (vertically oppo. angle)

angle BLD = angle CMD (each 90°)

so, ∆ BDL ~ ∆ CDM

BL/BD = CM/CD

HENCE

BL = CM (bcoz BD = CD given)

hence proved.

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