Question

plz tell answer of this diagramatic question ..need urgently​..surely mark u as brainlist.. find potential drop and current mainly=??​

Answer 1

R1 = 10Ω, R2 = 10Ω, R3 = 10Ω, R4 = 10Ω

R1 and R2 are in parallel

∴1/$R_{parallel}$ = 1/R1 + 1/R2

Also, we can use the formula R/n as both have equal resistance

1/$R_{parallel}$ = 1/10 + 1/10

1/$R_{parallel}$ = 1/5

$R_{parallel}$ = 5Ω

$R_{parallel}$, R3 and R4 are in series

∴ $R_{series}$ = $R_{parallel}$ + R3 +R4 = 5 + 10 +10

$R_{series}$ = 25Ω

Given, V = 100V (as per what I saw)

According to Ohm's law

I = V/R = 100/25 = 4A

Since I is the same for every resistor in series

I at R3 & R4 = 4V

V3 = IR3 = 4*10 = 40V

V4 = IR4 = 4*10 = 40V

$V_{parallel}$ = V - V3 - V4 = 20V

At R1 & R2, V is the same

So the potential drop at R1 and R2 (in parallel) is from 100V to 20V, while the potential drop at R3 is 20V to 40V and potential drop at R3 is 40V to 40V.

Hope I helped ☺☻

Answer 2

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