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In triangle ABC
AB=BC
Angle BAC=AngleBCA
IN∆ABC
BAC+BCA+ABC=180°
2BAC+40°=180°
2BAC=180°-40°
2BAC=140°
BAC=140°/2
BAC=70°
AB=BC
Angle BAC=AngleBCA
IN∆ABC
BAC+BCA+ABC=180°
2BAC+40°=180°
2BAC=180°-40°
2BAC=140°
BAC=140°/2
BAC=70°
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