Question

plz tell asap.
I am.confused
plz tell with the proper steps
thx ​

Answer 1

Answer:-

1) x + 90° = 125°

x = 125° - 90°

x = 35° ans.

2) 50 °+ 70° = x°

x° = 50° + 70°

x° =120° ans.

3) 30° + 40° = x°

x° = 30° + 40°

x = 70° ans.

4) x° + 2x° + 90° = 180°

3x° = 180° - 90°

3x° = 90°

x = 90° / 3 =30°

x = 30° ans.

5) y = 80°

x + y + 50° = 180°

x + 80° + 50° = 180°

x + 130° = 180°

x = 180° - 130°

x = 50°

x = 50° and y = 80° ans.

Answer 2

★ Solution (1) :-

First, we should find the value of ∠y.

Measure of ∠y :-

$\sf \leadsto Linear \: pair \: of \: angles = {180}^{\circ}$

$\sf \leadsto {125}^{\circ} + \angle{y} = {180}^{\circ}$

$\sf \leadsto \angle{y} = 180 - 125$

$\sf \leadsto \angle{y} = {55}^{\circ}$

Now, we can find the value of ∠x.

Measure of ∠x :-

$\sf \leadsto {Angle \: sum \: property}_{(Triangle)} = {180}^{\circ}$

$\sf \leadsto {90}^{\circ} + {55}^{\circ} + \angle{x} = {180}^{\circ}$

$\sf \leadsto {145}^{\circ} + \angle{x} = {180}^{\circ}$

$\sf \leadsto \angle{x} = 180 - 145$

$\sf \leadsto \angle{x} = {35}^{\circ}$

★ Solution (2) :-

First, we should find the value of ∠y.

Measure of ∠y :-

$\sf \leadsto {Angle \: sum \: property}_{(Triangle)} = {180}^{\circ}$

$\sf \leadsto {70}^{\circ} + {50}^{\circ} + \angle{y} = {180}^{\circ}$

$\sf \leadsto {120}^{\circ} + \angle{y} = {180}^{\circ}$

$\sf \leadsto \angle{y} = 180 - 120$

$\sf \leadsto \angle{y} = {60}^{\circ}$

Now, we can find the value of ∠x.

Measure of ∠x :-

$\sf \leadsto Linear \: pair \: of \: angles = {180}^{\circ}$

$\sf \leadsto {60}^{\circ} + \angle{x} = {180}^{\circ}$

$\sf \leadsto \angle{x} = 180 - 60$

$\sf \leadsto \angle{x} = {120}^{\circ}$

★ Solution (3) :-

First, we should find the value of ∠y.

Measure of ∠y :-

$\sf \leadsto {Angle \: sum \: property}_{(Triangle)} = {180}^{\circ}$

$\sf \leadsto {30}^{\circ} + {40}^{\circ} + \angle{y} = {180}^{\circ}$

$\sf \leadsto {70}^{\circ} + \angle{y} = {180}^{\circ}$

$\sf \leadsto \angle{y} = 180 - 70$

$\sf \leadsto \angle{y} = {110}^{\circ}$

Now, we can find the value of ∠x.

Measure of ∠x :-

$\sf \leadsto Linear \: pair \: of \: angles = {180}^{\circ}$

$\sf \leadsto {110}^{\circ} + \angle{x} = {180}^{\circ}$

$\sf \leadsto \angle{x} = 180 - 110$

$\sf \leadsto \angle{x} = {70}^{\circ}$

★ Solution (4) :-

Measure of ∠x :-

$\sf \leadsto {Angle \: sum \: property}_{(Triangle)} = {180}^{\circ}$

$\sf \leadsto x + 2x + {90}^{\circ} = {180}^{\circ}$

$\sf \leadsto 3x + {90}^{\circ} = {180}^{\circ}$

$\sf \leadsto 3x = 180 - 90$

$\sf \leadsto 3x = 90$

$\sf \leadsto x = \dfrac{90}{3}$

$\sf \leadsto x = {30}^{\circ}$

★ Solution (5) :-

Measure of ∠y :-

We no that the vertically opposite angles are always equal. So,

$\sf \leadsto \angle{y} = {80}^{\circ}$

Measure of ∠x :-

$\sf \leadsto {Angle \: sum \: property}_{(Triangle)} = {180}^{\circ}$

$\sf \leadsto {50}^{\circ} + {80}^{\circ} + \angle{x} = {180}^{\circ}$

$\sf \leadsto {130}^{\circ} + \angle{x} = {180}^{\circ}$

$\sf \leadsto \angle{x} = 180 - 130$

$\sf \leadsto \angle{x} = {50}^{\circ}$

Hence, solved !!