Question

plz tell fast.....both questions ​

Answer 1

The answer is above.

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Answer 2

fig 6.43

We are given PQ perpendicular to RS , PQ parallel SR <SQR= 28 and QRT= 65

<SQR=180-65=115

<QSR=180-(28+115). (angle sum)

=180-143

=37

therefore X=37 (alternative angles)

To find <PSQ

<PSQ=180-90+37(angle sum)

<PSQ=180-127

= 53

y= 53