Question

Plz tell fast...Bro and siss​

Answer 1

$\huge\mathbb{↑↑SOLUTION↑↑}$

Answer 2

$\huge{\underline{\underline{\bf{\purple{Solution}}}}}$

A.P

√2, 2√2, 3√2

First term = √2

common difference=2√2 -√2=√2(2-1)=√2

Sum of n terms

$\implies\sf S_n=\frac{n}{2}(2a+(n-1)d$

$\implies\sf S_n=\frac{n}{2}(2\sqrt{2}+(n-1)\sqrt{2}$

$\implies\sf S_n=\frac{n}{2}(2\sqrt{2}+\sqrt{2}n-\sqrt{2}$

$\implies\sf S_n=\frac{n}{2}(\sqrt{2}(2-1)+\sqrt{2}n$

$\implies\sf S_n=\frac{n}{2}(\sqrt{2}+\sqrt{2}n$

$\implies\sf S_n=\frac{n}{\sqrt{2}}+\frac{n^2}{\sqrt{2}}$

$\implies\sf S_n=\frac{n+n^2}{\sqrt{2}}=\frac{n(1+n)}{\sqrt{2}}$