Question

plz tell fast yyygehhegeyeye​

Answer 1

Answer:

$A:CH3CH=CH2,B:CH2ClCH=CH2</p><p></p><p></p><p>$

Explanation:

When propanol is heated with concentrated sulphuric acid at 443 K, dehydration takes place and prop-1-ene is formed. In this reaction concentrated sulphuric acid acts as a dehydrating agent.

$CH3CH2CH2OHconc.H2SO4170°Cprop−1−eneCH3−CH=CH2+H2O</p><p></p><p></p><p>Thus, A is CH3−CH=CH2.</p><p></p><p></p><p>At very high temperature, allylic substitution takes place.</p><p></p><p>CH3−CH=CH2Cl2500°CClH2C−CH=CH2+HCl</p><p></p><p></p><p>Thus, B is ClH2C−CH=CH2</p><p></p><p></p><p>$