Math, asked by adityatanu8034, 1 month ago

plz tell it solution​

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Answered by Sankalp050
4

Perimeter of Pentagon ABCDE = 5× side

=5×15

=75 cm

Area of a regular pentagon = pa/2,

where p = the perimeter and a = the apothem

P=75 cm

a= 10.32 cm

area  =  \frac{75 \times 10.32}{2}  \\  \\  = 387 \:  {cm}^{2}

Answered by snehaprajnaindia204
6

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Perimeter of Pentagon ABCDE

= 5 × side

= 5 × 15

= 75 cm

 \\

Area of a regular pentagon

= (p × a)/2,

where p = the perimeter and a = the apothem

 \\

  • P=75 cm

  • a= 10.32 cm

 \\  \\ AREA  =  \frac{pa}{2}  \\  \\  =  \frac{75 \times 10.32}{2}  \\  \\  = 75 \times 5.16 \\  \\  = 387 \\

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