Question

plz tell me answer with solving in your rough

don't give fake answers kindly solve un rough then send it to me

(1) find the area of the given figure ​

Answer 1

$\huge\mathfrak\red{☟ \: \: \: \: answer \: \: \: \: \: ✎}$

Area of Rectangles ABCD

$\: \: \: \: \: = length \times breadth$

$\: \: \: \: \: = 20 \times 6 \: or \: 120 \: {cm}^{2} ...(i)$

Area of Trapezium BEFC

$= \frac{1}{2} (sum \: of \: parallel \: sides) \times \: \: \: \: height$

$= \frac{1}{2} (6 + 12) \times 4 \: {cm}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \ \\ = 36 \: {cm}^{2} ..(ii)$

Area of Trapezium ADQP

$= \frac{1}{2} (sum \: of \: parall \: sides) \times he.$

$= \frac{1}{2} ( 6 + 14) \times 5 \: {cm}^{2} = 50 \: {cm}^{2} \: \: ..(iii)$

Area of the figure=

$= 120 \: {cm}^{2} + 36 \: {cm}^{2} + 50 \: {cm}^{2}$

$= 206 \: {cm}^{2}$

Please do not report if the answer is wrong, we have tried our best to give you the correct answer}

$\\ \\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$