Question

plz tell me fast ..
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Answer 1

Answer:

x9−1=(x−1)(x2+x+1)(x6+x3+1)

Explanation:

To factorize x9−1,

we can use the identity

a3−b3=(a−b)(a2+ab+b2).

Hence,

x9−1=(x3)3−13=(x3−1)(x6+x3+1)

factorizing x3−1 further

x9−1=(x3−1)(x6+x3+1)

= (x−1)(x2+x+1)(x6+x3+1)

Thus, it has 2 factors.

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