Question

plz tell me fast plzz​

Answer 1

Answer:

answer for the given problem is given

Answer 2

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$= > 2 {x}^{3} + {x}^{2} - 5x - 1$

To find p(2) & p(-2)

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Given :-

$= > 2 {x}^{3} + {x}^{2} - 5x - 1$

Put x=2

$= > p(2) = 2 {(2)}^{3} + {(2)}^{2} - 5(2) - 1$

$= > p(2) = 2(8) + 4 - 10 - 1$

$= > p(2) = 16 + 4 - 10 - 1$

$= > p(2) = 20 - 11 = 9$

$\bold{\red{= > p(2) = 9}}$

Now,put x=-2

$= > p( - 2) = 2 {( - 2)}^{3} + {( - 2)}^{2} - 5( - 2) - 1$

$= > p( - 2) = 2( - 8) + 4 + 10 - 1$

$= > p ( - 2) = - 16 + 4 + 10 - 1$

$= > p( - 2) = 14 - 17 = - 3$

$\bold{\red{ = > p( - 2) = - 3}}$

∴p(2)=9 & p(-2)=-3

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