Physics, asked by RiyaDhaka, 1 year ago

plz tell me How the path difference in young' double split experiment is = ? (as in the picture)

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Answered by Anonymous
2
let one eq be y = sin kx
another eq of interfere wave = y = sin( k(x+ delta x)

So, phase difference = K × delta x
As k = 2 × pie/ lambda

SO phase difference = 2 pie / lambda × pathdifference

so path difference = lambda/ 2 pie phase difference

RiyaDhaka: delta -phase difference & Δ -path difference ,delta =2π/lamda × x OK but X Ki jagh pr path difference. How? BTW Thnx
RiyaDhaka: Delta X is path difference then what is K? (sry I'm so confused )
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