Plz tell me how to find its root
Answers
Answer:
bro the ans is 32
Step-by-step explanation:
i think it will hepl u
Answer:
ok
Step-by-step explanation:
1 Rewrite 128128 as its prime factors.
\sqrt[4]{2\times 2\times 2\times 2\times 2\times 2\times 2}
4
2×2×2×2×2×2×2
2 Group the same prime factors into groups of four.
\sqrt[4]{(2\times 2\times 2\times 2)\times 2\times 2\times 2}
4
(2×2×2×2)×2×2×2
3 Rewrite each group of four in exponent form.
\sqrt[4]{{2}^{4}\times 2\times 2\times 2}
4
2
4
×2×2×2
4 Use this rule: \sqrt[4]{{x}^{4}}=x
4
x
4
=x.
2\sqrt[4]{2\times 2\times 2}
2
4
2×2×2
5 Simplify.
2\sqrt[4]{8}
2
4
8
6 Rewrite 88 as {2}^{3}2
3
.
2\sqrt[4]{{2}^{3}}
2
4
2
3
7 Use this rule: {({x}^{a})}^{b}={x}^{ab}(x
a
)
b
=x
ab
.
2\times {2}^{\frac{3}{4}}
2×2
4
3
8 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x
a
x
b
=x
a+b
.
{2}^{\frac{7}{4}}
2
4
7
Done.
mark me in brainliest.