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2) Given, volume of the cuboidal shaped soap bar = 150 cc.
Length and breadth of the cuboidal shaped soap bar are respectively 10 cm and 5 cm.
Let the thickness be "t".
By condition,
10×5×t = 150
Or, t = 150/50
Or, t = 3
Therefore the thickness of the cuboidal shaped soap bar is 3 cm (ANSWER).
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3) Volume of a brick = (25×15×10) cc or 3750 cc.
Volume of the wall = (6×2.5×0.5)m³ or 7.5 m³
Let "n" number of bricks are required to build the wall of volume 7.5 m³ or 7,500,000 cc.
Therefore, volume of n bricks = 3750n cc
By condition,
3750n = 7,500,000
Or, n = 2000
Therefore, the required number of bricks to build the wall of volume 7,500,000 cm³ is 2000 (ANSWER).
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