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Step-by-step explanation:
In triangle ADE,
AD = AE (given)
Angle ADE = Angle AED (angles opposite to equal sides are equal) ............(1)
In triangle ABE and triangle ACD,
AE = AD (given)
Angle AED = Angle ADE [proved earlier from (1)]
BD = CE (given)
Adding DE to both sides
BD + DE = CE + DE
BE = CD
So, triangle ABE is congruent to triangle ACD (by SAS)
Hence , proved
Hope it helps.
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