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Area of ∆ = 1/2[a1(b2-b3) + a2(b3-b1) + a3(b1-b2)]
= 1/2[5(7+4) + 4(-4-2) + 7(2-7)]
= 1/2[55 + (-24) + (-35)]
= 1/2[55 - 59]
= 1/2 × 4
Area of ∆ = 2 square units
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