Question

plz tell me the acidity of naoh​

Answer 1

Explanation:

Thus, 0.00126 moles of NaOH (Step 2) would interact with 0.00063 moles of tartaric acid. Divide the number of moles of the acid (Step 4) by the aliquot volume and then multiply by 100 to calculate the acid amount in 100 ml of the solution. In our example, amount (C4H6O6)=0.00063 moles x 100 ml/15 ml=0.0042 moles.

Answer 2

Answer:

$\huge \fcolorbox{lavender}{orange}{ans \: is \: 13}$

You can calculate pH if you know the concentration of the NaOH.

Explanation:

You will need to know the molarity of the NaOH. Let's assume the solution is 0.1M. NaOH is a strong base, so this will produce 0.1mol/L of OH ions in solution. This will produce a pH of 13.

You will need to take the negative log of 0.1 to find the pOH. This will work out to be 1.

Since pH + pOH = 14

We can calculate the pH to be 13.

This assumption we made about the base can only be used for strong bases which dissociate completely in water.

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