Question

plz tell me the ans​

Answer 1

Answe: 205%

Step-by-step explanation:

Answer 2

$\begin{gathered}\begin{gathered}\bf \: Given - \begin{cases} &\sf{Amount_{(7 \: years)} = Rs \: 7100} \\ &\sf{Amount_{(4 \: years)} = Rs \: 6200} \end{cases}\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\bf \: To\:find - \begin{cases} &\sf{Principal \: and \: Rate \: of \: interest}  \end{cases}\end{gathered}\end{gathered}$

$\begin{gathered}\Large{\bold{{\underline{Formula \: Used \::}}}} \end{gathered}$

$(1). \: \boxed{ \tt \: Simple interest, \: I = \dfrac{Principal \times Rate \times Time}{100} }$

$(2). \: \boxed{ \tt \: Amount = Principal + Simple interest}$

$\large\underline{\bold{Solution :- }}$

• Let Principal is Rs P

and

• Let Rate of interest be R % per annum.

• Let Simple Interest be represented by 'I'.

So,

$\large \underline{\tt \:{ According \: to \: statement }}$

$\rm :\longmapsto\:Amount_{(7years)} = Rs \: 7100$

$\rm :\implies\:\:{ \tt \: Principal + 7(Simple interest) = 7100}$

$\rm :\implies\:P \: + \: 7I = 7100 - - - (1)$

$\large \underline{\tt \:{ According \: to \: statement }}$

$\rm :\longmapsto\:Amount_{(4years)} = Rs \: 6200$

$\rm :\implies\:Principal + 4 \: (Simple interest) = Rs \: 6200$

$\rm :\implies\:P \: + \: 4I = 6200 - - - (2)$

Now,

• On Subtracting equation (2) from equation (1), we get

$\rm :\longmapsto\:3I = 900$

$\rm :\implies\:I = Rs \: 300$

Now,

• Substitute the value of I in equation (2), we get

$\rm :\longmapsto\:P + 4 \times 300 = 6200$

$\rm :\longmapsto\:P = 6200 - 1200$

$\rm :\implies\:P \: = \: 5000$

$\rm :\implies\: \boxed{ \bf \: Principal \: = \: Rs \: 5, \: 000}$

Now,

We have

• Simple interest for 1 year = Rs 300

and

• Principal, P = Rs 5000

So,

• Rate of interest is given by

$\rm :\longmapsto\:Rate = \dfrac{Simple \: interest \times 100}{Principal \times Time}$

$\rm :\longmapsto\:Rate = \dfrac{300 \times 100}{5000 \times 1}$

$\rm :\implies\: \boxed{ \bf \: Rate \: = \: 6 \: \% \: per \: annum \: }$