Question

plz tell me the answer

Answer 1

2.
in ABD and BAC

AB=AB common
BAC=ABC GIVEN
BC =AD GIVEN



TRIANGLES ARE CONGRUENT BY SAS RULE....

SO BD = AC & ABD=BAC BY CPCT....


hope you got your answer

Answer 2

(1) in triangle ABD and triangle BAC
AD=BC. Given
Angle DAB=angle CBA. Given
And AB= AB. Common
Therefore triangle ABD congruent BAC by ASA congruence
Therefore
BD=BC. CPct
And Angle ABD=angle BAC
(2). In triangle BOC and AOD
Angle BOC= Angle AOD. (V. O. A)
BC=AD. Given
Angle OAD=angle OBC
Therefore triangle are congruent by AAS congruence
Therefore OA= OC
There fore cd bisects Ab
(3) since l parallel m and p parallel q therefore the quadrilateral is parallelogram
Therefore in triangle ABC and cda
Bc=ad. Sides of parallelogram are equal
AB=dc. Same reason
And angle ABC =angle cda therefore
Triangle ABC congruent triangle cda
(4)in triangle apb and triangle aqb
ab=ab (common)
angle apb=angle aqb. Each 90
Angle bap =baq. Given l is bisector of angle a
Therefore triangle apb congruent aqb by sad rule
Therefore bp=bq. Cpct
Therefore b is equidistant from arms of angle b