Math, asked by kauramandeep4021, 7 months ago

plz tell me the answer ​

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Answered by payal8parkhe
2

Step-by-step explanation:

let assume. X is a small number

from second condition

second number is 12X

X+12X=130

13X=130

X=130/13

X=10

12X=12×10=120

the numbers are 10 and 120

this is your answer

let assume that numbers are x-1,X ,X+1,X+2

from condition

x-1+X +X+1+X+2=106

4X+2=106

4X=106-2

X=104/4

X=26

x-1=26-1=25

X=26

X+1=26+1=27

X+2=26+2=28

the consecutive years numbers are 25,26,27,&28

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Answered by SanskrutiBajaj
0

Answer:

9.

let no. be x and 12x

so, x+12x=130

13x=130

x=130/13

x=10

12x=120....answer

10.

sum of 4 consecutive number is 106

so,

x+x+1+x+2+x+3=106

4x+6=106

4x=106-6

4x=100

x=25

numbers are 25 26 27 28

hope this will help you

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