Question

plz tell me the answer for this question 3(x-5)+4(x-4)=2​

Answer 1

Answer:

Here is your right answer

Answer 2

$\huge\mathbb{SOLUTION:-}$

$\huge{\sf{Given :-}}$

• A linear equation of one variable which is x

• and we have to find the value of x

Now :-

$\sf\underline{\underline{\red{According\:To\: Question:-}}}$

$\sf 3(x-5)+4(x-4)=2\\ \\ \sf\implies 3x-15+4x-16=2\\ \\ \sf\implies 7x-31=2\\ \\ \sf\implies 7x=2+31\\ \\ \sf\implies x=\frac{33}{7}$

• The value of x is

• $\sf\implies \frac{33}{7}$

• NOW PUT THIS IN EQUATION TO CHECK OUR ANSWER

• IF L.H.S=R.H.S THEN OUR ANSWER IS CORRECT

$\boxed{\sf{\red{VERIFICATION:-}}}$

$\sf\leadsto 3(x-5)+4(x-4)=2\\ \\ \sf\implies 3x-15+4x-16=2\\ \\ \sf\implies \frac{3\times 33}{7}-15+\frac{4\times 33}{7}-16=2\\ \\ \sf\implies \frac{99}{7}+\frac{132}{7}-31=2\\ \\ \sf\implies \frac{99+132-217}{7}=2\\ \\ \sf\implies \frac{231-217}{7}=2\\ \\ \sf\implies \cancel{\frac{14}{2}}=2\\ \\ \sf\implies 2=2$

$\:\:\:\:\sf L.H.S=R.H.S\:\:\:\:\:\:\: \bf hence\: verified!$

$\boxed{\boxed{\boxed{\red{\sf{x=\frac{33}{7}}}}}}$

#BAL

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