Question

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Answer 1

Answer:

Hope it will help you

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given: ABCD is a parallelogram

with AP bisector to BD & CQ bisector to BD

to prove: triangle APB congruent with to triangle CQD

Proof:

ABDC

(Opposite sides of parallelogram are parallel

and transversal BD.)

ABP = CDQ. (Alternate angles) (1)

In APB and CQD,

APB- CQD (Both are 90")

ABP = CDQ (From (1)

AB = CD (Opposite sides of parallelogram are equal)

AAPB ACQD ( AAS congruence rule)

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