plz tell me the answer if you can do it......
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take LCM as AcubeBcubeCcube
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Answer:
Step-by-step explanation:
Given,
a³/b³c³+ b³/c³a³+c³/a³b³-3/abc
On taking LCM of b³c³, c³a³, and a³b³ you will get a³b³c³ as LCM.
(a^6+ b^6+ c^6)-3 a²b²c²)/a³b³c³
further solution can be determined by utilizing different formula
On taking LCM and solving further you will get the desired answer on applying the formula of
a³+b³+c³-3 abc = 0 of a+b+c = 0
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