Math, asked by ichchhajain21, 8 days ago

plz tell me the answer of 16 ques​

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Answers

Answered by TheCrusher
2

\Large{\underline{\underline{\mathfrak{Answer :}}}}

The value of x is -2.

_____________________

\Large{\underline{\underline{\mathfrak{Explanation :}}}}

\sf{\implies ({\frac{2}{5}})^{-5} \times ({\frac{2}{5}})^{-11} = ({\frac{2}{5}})^{8x}}

We know that,

\underline{\boxed{\boxed{\bf{ a^{m} \times a^{n} = a^{m + n}}}}}

_________________[Putting Values]

\sf{\implies ({\frac{2}{5}})^{-5 - 11} = ({\frac{2}{5}})^{8x}}

\sf{\implies ({\frac{2}{5}})^{-16} = ({\frac{2}{5}})^{8x}}

Now,

Since bases are same, we can equate the powers,

\sf{\implies -16 = 8x} \\ \\ \sf{\implies x = \frac{-\cancel{16}}{\cancel{8}}} \\ \\ \sf{\implies x = -2}

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