Math, asked by shauryapra60, 2 days ago

plz tell me the answer plz fast​

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Answered by DEBOBROTABHATTACHARY
1

x^8 + 1/x^8 - 2

= (x^4)^2 - 2.(x^2).(1/x^2) + (1/x^4)^2

= (x^4 - 1/x^4)^2

= {(x^2)^2 - (1/x^2)^2}^2

= (x^2 + 1/x^2)^2 (x^2 - 1/x^2)^2

= (x^2 + 1/x^2)^2 {(x + 1/x) (x - 1/x)}^2

= (x^2 + 1/x^2)^2 (x + 1/x)^2 (x - 1/x)^2

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