Plz..
Tell me the correct options only..
No spam Plz.. No solutions Plz..
Q. 20, 21, 23, 24, 26, 29
Attachments:
Anonymous:
20.) 2
Answers
Answered by
0
Hey mate here is your answer 》》》》
Three charges each equal to q are placed at three corners A, B and C of a square ABCD of side length a.
we have to find net electric field at D
electric field due to A on D = kq/(√2a)² = kq/2a²
electric field due to B on D = kq/a²
Let kq/a² = E
then, net electric field at D = resultant of electric field due to B and C on D + electric field due to A
= √(E² + E²) + E/2
= √2 E + E/2
= (2√2 + 1)E/2
hence, electric field at fourth corner is (2√2 + 1)/2 × kq/a²
Similar questions
Science,
5 months ago
Math,
5 months ago
Computer Science,
5 months ago
Math,
10 months ago
Chinese,
1 year ago