Question

PLZ TELL ME THIS ANSWER​

Answer 1

Answer:

Question :-

$\mapsto \bf{\dfrac{5(1 - x) + 3(1 + x)}{1 - 2x} =\: 8}$

To Find :-

• What is the value of x.

Solution :-

$\bigstar\: \: \sf\bold{\purple{\dfrac{5(1 - x) + 3(1 + x)}{1 - 2x} =\: 8}}$

$\leadsto \bf{\dfrac{5(1 - x) + 3(1 + x)}{1 - 2x} =\: 8}$

$\longrightarrow \sf \dfrac{5 - 5x + 3 + 3x}{1 - 2x} =\: 8$

$\longrightarrow \sf \dfrac{- 5x + 3x + 3 + 5}{1 - 2x} =\: 8$

$\longrightarrow \sf \dfrac{- 2x + 8}{1 - 2x} =\: 8$

By doing cross multiplication we get,

$\longrightarrow \sf - 2x + 8 =\: 8(1 - 2x)$

$\longrightarrow \sf - 2x + 8 =\: 8 - 16x$

$\longrightarrow \sf - 2x + 16x =\: 8 - 8$

$\longrightarrow \sf 14x =\: 0$

$\longrightarrow \sf x =\: \dfrac{0}{14}$

$\longrightarrow \sf\bold{\red{x =\: 0}}$

${\small{\bold{\underline{\therefore\: The\: value\: of\: x\: is\: 0\: .}}}}$

Answer 2

$\: \: \: \: \: \: \: \: \: \: \: ❍ \: \: \large \boxed{ \underline{ \pmb { \sf \: Question}}} \\ \\ \\ \: \: \: ❍ \: \: \: \: \rm \dfrac{5(1 - x) + 3(1 + x)}{1 - 2x} = 8$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ❍ \: \: \large \boxed{ \underline{ \pmb { \sf \: Find}}} \\ \\ \: \dashrightarrow \: \rm What \: is \: the \: value \: of \: x \: ?$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ❍ \: \: \large \boxed{ \underline{ \pmb { \sf \: Solution}}} \\ \\ \: \: \: \pink❍ \: \: \: \rm \dfrac{5(1 - x) + 3 (1+x }{1 - 2x} = 8 \\ \\ \: \: \: \red❍ \rm \: \: \: \: \: \dfrac{5 - 5x + 3 + 3x}{1 - 2x} = 8 \\ \\ \: \: \: \blue❍ \: \: \: \: \rm \dfrac{ - 5x + 3x + 3 + 5}{1 - 2x} = 8 \\ \\ \green❍ \: \: \: \: \rm \frac{ - 2x + 8}{1 - 2x} = 8$

$\: \: \: \: \: \: \: \: \: \: \: ❍ \: \: \large \boxed{ \underline{ \pmb { \sf \: Cross \: multiplication}}} \\ \\ \dashrightarrow \: \rm - 2x + 8 = 8(1 - 2x) \\ \\ \dashrightarrow \: \rm - 2x + 8 = 8 - 16x \\ \\ \dashrightarrow \: \rm - 2x + 16x = 8 - 8 \\ \\ \dashrightarrow \: \rm14x = 0 \\ \\ \dashrightarrow \: \rm \: x = \dfrac{0}{14} \\ \\ \dashrightarrow \: \rm \: x = 0$

$\: \: \: \: \: \: \: \: \therefore \: \: \: \: {\underline{\underline{\rm The \: value \: of \: x = 0}}}$