Question

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Answer 1

Answer:

what is the mass percentage of butyric acid for each element when the values of  Co2 and H2O are given?

find molecular mass formula for butyric acid determined experimentally as 88amu.

Explanation:

In CO2 the no of C atom is 1.

it means 44 mg of CO2  = 12 mg C

and 8.45 mg  = 12 X 8.45 / 44

                      =2.30mg

% of C = 2.30 X 100  / 4.24

          = 54.3 %

Similarly in H2O = 2H

              in 3.46mg of H2O H = 2 X 3.46 /18

               = 0.384mg

% of H = 0.348 x100 / 4.24  =9 %

% of O = 100 - 63.3

= 36.7%

By calculation we get the simple whole no ratio = 2:4:1

so empirical formula is C2H4O

and the value of n= 88 /44 =2

so molecular formula = c4 H8 O2