Question

plz tell me this question's answer if don know don't answer and do it in copy​

Answer 1

The answer:

0.2M = 0.2 mole/L

Therefore, 0.5L * 0.2M = 0.1 mole of H2SO4 required.

The molar mass of H2SO4 is 98.079 g/mole (see periodic table or google).

Therefore, 98.079 g/mole * 0.1 mole = 9.8079 g

9.8079 g/ 1.84 g/cm^3 = 5.33038 cm^3 (=5.33038 mL)

The purity of your substance is 96%, therefore you will actually need:

5.33038*(1/0.96) = 5.55248 mL.

The required precision in your answer is 3 digits (due to the precision of 500 mL).

Therefore, the answer is 5.55 mL of acid and (500–5.55 =) 494 mL of water.

Note that when preparing such a dilution, always add acid to water. Never the other way around. Pure H2SO4 is an extremely dangerous substance. Handle only under the supervision of a professional.

hope u got ur answer