Question

Plz tell. Plz plz plz plz plz

Answer 1

Take L.C.M in the L.H.S we have

[x²+(x+1)²]/[x(x+1)] = 13/6,


[x²+x²+1+2x]/(x²+x) = 13/6,

(x²+2x+1)/(x²+x) = 13/6,

6x²+12x+6=13x²+13x,

then

0=13x²-6x²+13x-12x-6,


0=7x²+x-6,

then

7x²+x-6=0,

7x²+(7-6)x-6=0,

7x²+7x-6x-6=0,

7x(x+1)-6(x+1)=0,

(x+1)(7x-6)=0,

if
x+1=0,

then
x=-1,


if
7x-6=0,

then
x=6/7