Question

plz tell question -5​

Answer 1

Answer:

$m = 6 \: and \: n = 3$

Step-by-step explanation:

$number \: of \: subsets \: of \: first \: set = {2}^{m} \\ numberof \: subset \: of \: second \: subset = {2}^{n} \\ now \\ {2}^{m} - {2}^{n} = 56 \\ {2}^{n} ( {2}^{m - n} - 1) = 8 \times 7 \\ now \: on \: comparing \: \: we \: get \\ {2}^{ n} = 8 \\ {2}^{n} = {2}^{3} \\ n = 3 \\ and \\ {2}^{m - n} = 7 \\ {2}^{m - n} = 7 + 1 \\ {2}^{m - n} = 8 \\ {2}^{m - n} = {2}^{3} \\ on \:comparing \: exponent \\ m - n = 3 \\ putting \: n = 3 \: we \: get \\ m - 3 = 3 \\ m = 3 + 3 \\ m = 6$