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x^2 + y^2 -4x - 2y + k = 0
so, (x-2)^2 - 4 + (y - 1)^2 - 1 + k = 0
(x-2)^2 + (y-1)^2 = 5 - k
so, r^2 = (5 - k) sq. units.
We are given, area = 25π
so. π(5-k) = 25π
so, 5 - k = 25
Hence, k = -20
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