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Step-by-step explanation:
AE is the bisector of the exterior angle ∠DAC of the Δ ABC and AE || BC
Now,
AB || BC {given}
∠1 = ∠2 {given}
So, ∠B = ∠1 {Corresponding angle}
and ∠C = ∠2 {Alternate angle}
=> ∠B = ∠C
=> AB = AC
So, Δ ABC is an isosceles triangle.
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