Question

plz tell the answer​

Answer 1

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Q1) find the roots of the equation 4x+3y=12

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$\: \: \divideontimes \underline{\bf{substiute \: x = 0}}$

$\: \: \implies \displaystyle \sf{4(0) + 3y = 12}$

$\ \: \implies \displaystyle \sf{3y = 12}$

$\: \: \implies \displaystyle \sf{y = \frac{12}{3} = 4}$

Solution are x=0 and y=4

$\: \: \divideontimes \underline{ \bf \: substitute \: x = 1}$

$\: \: \implies \displaystyle \tt{4(1) + 3y = 12}$

$\: \: \implies \displaystyle \rm{3y = 8}$

$\: \: \implies \displaystyle \rm{y = \frac{8}{3} }$

Solution are x=1 and y=8/3

$\: \: \boxed{ \bf{this \: equation \: has \: infinite \: roots \: by \: putting \: x \: value \: we \: get \: different \: y \: values}}$