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as per the therom of parallelogram that the diagnol of a parallelogram bisect each other.
therefore, AO=OC AND BO=OD
therefore BO=1/2BD
S0,BO=6.8CM
SIMILARLY AO=1/2AC
SO,AO=3.4
Answered by
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i)AO is obviously equal to CO as the diagonals of a IIgm bisect each other.
So, AO=4 cm
ii)From above, we got that the diagonals of a IIgm bisect each other.
So, AC=2 OC
AC=2*4=8 cm
iii)A/q, BD=AC+5
or BD=8+5
or BD=13 cm
iv)As the diagonals of a IIgm bisect each other. So,BO=1/2*BD
or BO=13/2
or BO=6.5 cm
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