Question

plz tell the answer
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Answer 1

Answer :

$\frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } = a + b \sqrt{6} \\ \\ \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ \\ \frac{( \sqrt{3} + \sqrt{2}) {}^{2} }{( \sqrt{3}) {}^{2} - ( \sqrt{2}) {}^{2} } \\ \\ \frac{3 + 2 + 2 \sqrt{6} }{3 - 2} \\ \\ \boxed{ \bf 5 + 2 \sqrt{6} }$

Therefore, a = 5 and b = 2.

Answer 2

HeRe Is Your Ans

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$\frac{ \sqrt{3} \: + \: \sqrt{2} }{ \sqrt{3} \: - \: \sqrt{2} } \times \frac{ \sqrt{3} \: + \: \sqrt{2} }{ \sqrt{3} \: + \: \sqrt{2} } \\ \\ \frac{3 + 2 + \sqrt[2]{6} }{3 - 2} \\ \\ 5 \: + \sqrt[2]{6}$

Hence , A = 5 And B = 2

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