Question

plz tell the answer fast

Answer 1

part A is a isoceles triangle whose sides are a=5cm,b=5cm,c=1cm
by using herons formula
s=a+b+c/2
s=5+5+1/2
s=11/2
s=5.5
area of isoceles triangle=
$\sqrt{s(s - a)(s \ - b)(s - c)}$
=2.47cm
part 2
part 2 is a rectangle
l=6.5cm
b=1cm
are of rectangle=l
$lenght \times breadth$
=6.5cm2

Answer 2

Hey mate
your answer is
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Solve :-
For area 1
a = 5 cm
b = 5 cm
c = 1 cm
.°. , s = a+b+c/2
= 5+5+1/2
= 11/2
= 5.5 cm

.°. , area 1 = √s(s-a)(s-b) (s-c)
= √5.5(5.5-5)(5.5-5)(5.5-1)
= √5.5(0.5)(0.5)(4.5)
= 0.5√(5.5)(4.5)
= 0.5√ (0.5)(11)(0.5)(9)
= (0.5)(0.5)(3)√11
= 0.75√11 = 0.75(3.3) (approximately)
= 2.5 cm Square (approximately)
Area 2. = 6.5(1) = 6.5 CM square

For area 3
area 3 = 1/2(2)(√3/2)+1/2(1)(√3/2)
= √3/2+ √3/4
= 3√3/4 = 3(1.732)/4 (approximately)
= 5.196/4 = 1.3 CM Square (aprox.)
area 4 = 6(1.5)/2 = 4.5 CM Square
area 5 = 6(1.5)/2 = 4.5 CM Square

.°. , Total area of the paper used =
area 1 +area 2 + area 3 + area 4 + area 5
(2.2 + 6.5 + 1.3 + 4.5 + 4.5)cm square
19.3 CM square
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hope it works for you
mate
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